Varun Chakaravarthy Dismisses Glenn Maxwell in 4th T20I, Leaving Australia Struggling
Varun Chakaravarthy took the prized wicket of Glenn Maxwell in the fourth T20I between India and Australia at Carrara Oval, Queensland, on Thursday, November 6. The leg-spinner dismissed Maxwell for just 2 runs, leaving Australia reeling at 103/6.
The wicket fell in the 15th over of Australia’s chase. Varun bowled a googly, and Maxwell fell into the trap. The right-handed batsman gave himself room to play it towards the offside but missed completely. The ball struck the top of the off-stump before entering the wicketkeeper’s gloves.
Chakaravarthy finished with figures of 1/26 from his four overs. The World No.1 T20I-ranked bowler has taken five wickets in the series and 26 wickets across 15 matches this year.
India Maintains Upper Hand in the Match
A clinical bowling performance helped India maintain the upper hand in the fourth T20I. At the time of writing, Australia were 116/8 after 17 overs, with Ben Dwarshuis and Nathan Ellis at the crease.
- Axar Patel, Shivam Dube, and Washington Sundar each took two wickets.
- Shivam Dube also removed Tim David for 14 runs off nine balls.
India’s Batting Performance
Sent in to bat first, India posted a total of 167/8 in their 20 overs. Vice-captain Shubman Gill top-scored with 46 runs off 39 balls, including one six and four boundaries. Abhishek Sharma, Shivam Dube, and captain Suryakumar Yadav also contributed scores in the twenties.
Axar Patel provided a strong finish, scoring an unbeaten 21 off 11 balls.
“Varun bowling a googly to dismiss Maxwell was a key moment in the match,” said an analyst.
Summary: Varun Chakaravarthy’s crucial wicket and India’s strong bowling display kept Australia under pressure in the fourth T20I, with India setting a competitive total and maintaining control.